document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=754111>Question 754111</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how much of an alloy that is 40 copper should be mixed with 100 ounces of an alloy that is 90% copper in order to get an alloy that is 50% copper? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #458791 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=458791\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> how much of an alloy that is 40 copper should be mixed with 100 ounces of an alloy that is 90% copper in order to get an alloy that is 50% copper?<BR>\n" );
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document.write( "let x=amount 0f 40% copper to be mixed<BR>\n" );
document.write( "x+100=amt of 50% alloy mixture<BR>\n" );
document.write( "40%x+90%*100=50%(x+100)<BR>\n" );
document.write( ".4x+90=.5x+50<BR>\n" );
document.write( ".10x=40<BR>\n" );
document.write( "x=400<BR>\n" );
document.write( "amount of 40% copper to be mixed with 100 ounces of an alloy that is 90% copper=400 ounces </SPAN>\n" );
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