document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=753885>Question 753885</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 24-6x^2=0   -complete the square\r<BR>\n" );
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document.write( "x^2-x-4=8 complete the square \r<BR>\n" );
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document.write( "-3x^2=7x+2 complete the square </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #458755 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=458755\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 24-6x^2=0 -complete the square<BR>\n" );
document.write( "since there is no x-term, can't complete the square.<BR>\n" );
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document.write( "x^2-x-4=8 complete the square<BR>\n" );
document.write( "Take 1/2 the coefficient of the x-term, then add its square. Add the same amt to other side of equation to maintain equality.<BR>\n" );
document.write( "(x^2-x+1/4)=12+1/4 (add 1/4 to maintain equality)<BR>\n" );
document.write( "(x-1/2)^2=49/4<BR>\n" );
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document.write( "-3x^2=7x+2 complete the square<BR>\n" );
document.write( "-3x^2-7x=2<BR>\n" );
document.write( "-3(x^2-7x/3+49/36)=2-49/12 (add -3*49/36=-49/12 to maintain equality)<BR>\n" );
document.write( "-3(x-7/6)^2=-25/12 </SPAN>\n" );
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