document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=753973>Question 753973</A>: <I><SPAN STYLE=\"word-break: break-all;\"> You are given the coordinates of the vertex   (0,-4)  and of a point   (-9,-6)   on a parabola. Find the coefficients for the equation of the parabola. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #458706 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=458706\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You are given the coordinates of the vertex (0,-4) and of a point (-9,-6) on a parabola. Find the coefficients for the equation of the parabola.<BR>\n" );
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document.write( "Standard (vertex) form of equation for a parabola: y=A(x-h)^2+k, (h,k)=(x,y) coordinates of the vertex, A is a coefficient that affects the slope or steepness of the curve.<BR>\n" );
document.write( "solving for A:<BR>\n" );
document.write( "y=A(x-h)^2+k<BR>\n" );
document.write( "-6=A(-9-0)^2-4<BR>\n" );
document.write( "81A=-2<BR>\n" );
document.write( "A=-2/81<BR>\n" );
document.write( "equation: y=(-2/81)(x)^2-4 </SPAN>\n" );
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