document.write( "Question 753778: y varies directly as x and inversely as the square of z. y= 38 when x=32 and z=4. Find y when x=75 and z=5.
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Algebra.Com's Answer #458644 by Cromlix(4381)\"\" \"About 
You can put this solution on YOUR website!
y varies directly as x and inversely as the
\n" ); document.write( "square of z
\n" ); document.write( "y = kx/z^2
\n" ); document.write( "(k is the constant of proportionality)
\n" ); document.write( "Using the given values find out k's value\r
\n" ); document.write( "\n" ); document.write( "y = kx/z^2
\n" ); document.write( "38 = k *32/ 4^2
\n" ); document.write( "38 = 32k/16
\n" ); document.write( "38 = 2k
\n" ); document.write( "k = 19
\n" ); document.write( "Put back in formula\r
\n" ); document.write( "\n" ); document.write( "y = 19x/z^2\r
\n" ); document.write( "\n" ); document.write( "y = 19*75/5^2
\n" ); document.write( "y = 1425/25
\n" ); document.write( "y = 57
\n" ); document.write( "Hope this helps
\n" ); document.write( ":-)
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