document.write( "Question 753750: A mixture containing 16% of a drug is to be combined with another mixture containing 28% of a drug to obtain 15 ml of a 24% mixture. How much 16% mixture is required? \n" ); document.write( "

Algebra.Com's Answer #458587 by josgarithmetic(39618) $\"\"$ $\"About$

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(percent mixture wanted) = (amount of pure drug)/(mixture)\r
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\n" ); document.write( "\n" ); document.write( "Amount of just the drug is $\"0.16%2Ax%2B0.28%2Ay\"$
\n" ); document.write( "Amount of mixture obviously was given, 15 ml.
\n" ); document.write( "This uses x for amount of the 16 drug and y for the amount of the 28% drug.\r
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\n" ); document.write( "\n" ); document.write( "The FRACTION of the mixture as drug we want is 0.24, which means same as 24%.\r
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\n" ); document.write( "\n" ); document.write( "Put everything in place:
\n" ); document.write( " $\"%280.16x%2B0.28y%29%2F15=0.24\"$ AND $\"x%2By=15\"$
\n" ); document.write( "Solving this system should not be any trouble.\r
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