document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=753651>Question 753651</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The directions are: use a double angle identity to find the exact value of each expression. <BR>\n" );
document.write( "The problem is: csc300(degrees) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #458568 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=458568\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The directions are: use a double angle identity to find the exact value of each expression. <BR>\n" );
document.write( "The problem is: csc300(degrees)<BR>\n" );
document.write( "csc 300º=1/sin 300º<BR>\n" );
document.write( "=1/(sin 2(150º))<BR>\n" );
document.write( "=1/(2sin(150º)cos(150º))<BR>\n" );
document.write( "=1/(2*1/2*-&#8730;3/2)<BR>\n" );
document.write( "=1/(-&#8730;3/2)=-2&#8730;3<BR>\n" );
document.write( "=-2&#8730;3/3 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );