document.write( "Question 753680: how much pure acid should be mixed with 3 gallons of 20% acid solution to get a 40% acid solution? \n" ); document.write( "
Algebra.Com's Answer #458560 by tommyt3rd(5050)![]() ![]() You can put this solution on YOUR website! unknown amt: x\r \n" ); document.write( "\n" ); document.write( "20% acid: 3(0.2)\r \n" ); document.write( "\n" ); document.write( "new mixture: (x+3)(0.4)\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x=1\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( ":) \n" ); document.write( " |