document.write( "Question 753680: how much pure acid should be mixed with 3 gallons of 20% acid solution to get a 40% acid solution? \n" ); document.write( "
Algebra.Com's Answer #458560 by tommyt3rd(5050)\"\" \"About 
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unknown amt: x\r
\n" ); document.write( "\n" ); document.write( "20% acid: 3(0.2)\r
\n" ); document.write( "\n" ); document.write( "new mixture: (x+3)(0.4)\r
\n" ); document.write( "\n" ); document.write( "\"%0D%0Ax%2B%283%29%280.2%29=%28x%2B3%29%280.4%29%0D%0A\"\r
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\n" ); document.write( "\n" ); document.write( "x=1\r
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