document.write( "Question 753693: Students in an english class took a final exam. They took quivalent forms of the exam at monthly intervals thereafter. The average score S(t), in percent, after t months was found to be given by:\r
\n" ); document.write( "\n" ); document.write( " S(t) = 68-20 log (t + 1),t > or = to 0.\r
\n" ); document.write( "\n" ); document.write( "1.What is the average score when they initially took the test, t=0?\r
\n" ); document.write( "\n" ); document.write( "2.What is the average score after 14 months?\r
\n" ); document.write( "\n" ); document.write( "3.After what time t was the average score of 40%?
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Algebra.Com's Answer #458533 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
Students in an english class took a final exam. They took quivalent forms of the exam at monthly intervals thereafter. The average score S(t), in percent, after t months was found to be given by:
\n" ); document.write( "S(t) = 68-20 log (t + 1),t > or = to 0.
\n" ); document.write( "1.What is the average score when they initially took the test, t=0?
\n" ); document.write( "S(0) = 68-20*log(1) = 68-20*0 = 68
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\n" ); document.write( "2.What is the average score after 14 months?
\n" ); document.write( "S(14) = 68-20*log(15) = 68-23.52 = 44.48
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\n" ); document.write( "3.After what time t was the average score of 40%?
\n" ); document.write( "40 = 68-20*log(t+1)
\n" ); document.write( "20*log(t+1) = 68-40
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\n" ); document.write( "20*log(t+1) = 28
\n" ); document.write( "log(t+1) = 1.4
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\n" ); document.write( "t+1 = 10^1.4 = 25.12
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\n" ); document.write( "t = 24.12
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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