document.write( "Question 753693: Students in an english class took a final exam. They took quivalent forms of the exam at monthly intervals thereafter. The average score S(t), in percent, after t months was found to be given by:\r
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document.write( " S(t) = 68-20 log (t + 1),t > or = to 0.\r
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document.write( "1.What is the average score when they initially took the test, t=0?\r
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document.write( "2.What is the average score after 14 months?\r
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document.write( "3.After what time t was the average score of 40%? \n" );
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Algebra.Com's Answer #458533 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Students in an english class took a final exam. They took quivalent forms of the exam at monthly intervals thereafter. The average score S(t), in percent, after t months was found to be given by: \n" ); document.write( "S(t) = 68-20 log (t + 1),t > or = to 0. \n" ); document.write( "1.What is the average score when they initially took the test, t=0? \n" ); document.write( "S(0) = 68-20*log(1) = 68-20*0 = 68 \n" ); document.write( "---------------------------------------- \n" ); document.write( "2.What is the average score after 14 months? \n" ); document.write( "S(14) = 68-20*log(15) = 68-23.52 = 44.48 \n" ); document.write( "-------------------------------------------------- \n" ); document.write( "3.After what time t was the average score of 40%? \n" ); document.write( "40 = 68-20*log(t+1) \n" ); document.write( "20*log(t+1) = 68-40 \n" ); document.write( "---- \n" ); document.write( "20*log(t+1) = 28 \n" ); document.write( "log(t+1) = 1.4 \n" ); document.write( "--- \n" ); document.write( "t+1 = 10^1.4 = 25.12 \n" ); document.write( "--- \n" ); document.write( "t = 24.12 \n" ); document.write( "===================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "===================== \n" ); document.write( " \n" ); document.write( " |