document.write( "Question 753662: Find the value of the 6 trigometric functions of the following showing the steps to get each trigometric function where an angle is\r
\n" ); document.write( "\n" ); document.write( "1.)opposite=4
\n" ); document.write( "Hypotinuse 5
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\n" ); document.write( "\n" ); document.write( "2.)opposite=2
\n" ); document.write( "Hypotinuse is 5\r
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Algebra.Com's Answer #458516 by solver91311(24713)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "There is no such thing as a hypotinuse. The side opposite the right angle in a right triangle is a hypotenuse. You probably misspelled it because you are mispronouncing it. hī-ˈpä-tə-ˌnüs NOT hī-ˈpä-tin-ˌüs\r
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\n" ); document.write( "\n" ); document.write( "The sine is the opposite divided by the hypotenuse\r
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\n" ); document.write( "\n" ); document.write( "The cosine is the adjacent divided by the hypotenuse\r
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\n" ); document.write( "\n" ); document.write( "The tangent is the sine divided by the cosine which reduces to the opposite divided by the adjacent\r
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\n" ); document.write( "\n" ); document.write( "The cotangent is the reciprocal of tangent\r
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\n" ); document.write( "\n" ); document.write( "The secant is the reciprocal of cosine\r
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\n" ); document.write( "\n" ); document.write( "The cosecant is the reciprocal of sine\r
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\n" ); document.write( "\n" ); document.write( "Use Pythagoras to find the measure of the missing side in your second problem. Leave the value in radical form, but remember to rationalize your denominators when you calculate the trig functions.\r
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\n" ); document.write( "\n" ); document.write( "John
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\n" ); document.write( "Egw to Beta kai to Sigma
\n" ); document.write( "My calculator said it, I believe it, that settles it
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