document.write( "Question 65312: Suppose a cannon shoots a cannon ball into the air so that the initial upward velocity of the cannon ball is 320 feet per second.Assume the cannon ball is shot from ground level. \r
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document.write( "H=-1/2*gt^+vt+h where g is the acceleration due to gravity, and on the earth, equals 32ft/sec^ (English units) or 9.8m/sec^(metric units,\r
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document.write( "v is the initial upward velocity of the object
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document.write( "h is the initial height above the ground\r
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document.write( "the question:
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document.write( " how high will the cannon ball be in 7 seconds?
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document.write( "and how do you figure it out?\r
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document.write( "i tried -16x^+320*7 because i thought this is what the solver was telling me to do...my answers were 2256,2224,2128,and 2352. None of these appear to be correct. I answered question #1 by guessing: in 5 seconds, the rocket will be 1200 feet above ground. The solution I came up with was 320*5=1600, 16*5=80,then add 320+80=400, then subtract 400 from 1600 to get 1200feet, which was the correct answer , but for question #2, i am wrong if i use the same pattern. \n" );
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Algebra.Com's Answer #45850 by Earlsdon(6294)![]() ![]() ![]() You can put this solution on YOUR website! The equation that relates the height (as a funtion of time) of an object propelled upwards at an initial velocity of Vo from an initial height of Ho is: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "The cannon ball will reach a height of 1,456 feet in 7 seconds. \n" ); document.write( " |