document.write( "Question 8330: can you please really help me with this question.. it will really help me alot..
\n" ); document.write( "solve by any method.
\n" ); document.write( "-2x+10=0
\n" ); document.write( "2x-2y=6 \n" ); document.write( "

Algebra.Com's Answer #4585 by gsmani_iyer(201) $\"\"$ $\"About$

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\n" ); document.write( " -2x + 10 = 0 ......................(1)
\n" ); document.write( " 2x + 2y = 6 ......................(2)\r
\n" ); document.write( "\n" ); document.write( " Let's take the equation (1)
\n" ); document.write( " -2x + 10 = 0
\n" ); document.write( " So -2x = -10
\n" ); document.write( " x = $\"-10%2F-2\"$
\n" ); document.write( " x = 5 ............................(3)
\n" ); document.write( " Now replacing the value of x in eq.no.(2), we get
\n" ); document.write( " (2*5) + 2y = 6
\n" ); document.write( " =10 + 2y = 6
\n" ); document.write( " =2y = 6-10 = -4
\n" ); document.write( " 2y = -4
\n" ); document.write( " y = $\"-4%2F2\"$ = -2
\n" ); document.write( "
\n" ); document.write( " So, x = 5; y = -2; Answer
\n" ); document.write( " \n" ); document.write( "

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