document.write( "Question 753648: how do you do the problem 3x-5=7 and 3x/2=3
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Algebra.Com's Answer #458490 by Cromlix(4381)![]() ![]() You can put this solution on YOUR website! I understand that these are two separate problems. \n" ); document.write( "3x - 5 = 7 \n" ); document.write( " 3x = 7 + 5 \n" ); document.write( " 3x = 12 \n" ); document.write( " x = 12/3 \n" ); document.write( " x = 4\r \n" ); document.write( "\n" ); document.write( "3x/2 = 3 \n" ); document.write( "Multiply both sides by 2 \n" ); document.write( " 3x = 6 \n" ); document.write( " x = 6/3 \n" ); document.write( " x = 2\r \n" ); document.write( "\n" ); document.write( "To check you can always put the answers \n" ); document.write( "back into the original equations:- \n" ); document.write( "3x - 5 = 7 \n" ); document.write( "3*4 - 5 = 7 \n" ); document.write( "12 - 5 = 7 which is correct \n" ); document.write( "3x/2 = 3 \n" ); document.write( "3*2/2 = 3 \n" ); document.write( "6/2 = 3 which is correct. \n" ); document.write( "Hope this helps \n" ); document.write( ":-) \n" ); document.write( " |