document.write( "Question 753648: how do you do the problem 3x-5=7 and 3x/2=3
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Algebra.Com's Answer #458490 by Cromlix(4381)\"\" \"About 
You can put this solution on YOUR website!
I understand that these are two separate problems.
\n" ); document.write( "3x - 5 = 7
\n" ); document.write( " 3x = 7 + 5
\n" ); document.write( " 3x = 12
\n" ); document.write( " x = 12/3
\n" ); document.write( " x = 4\r
\n" ); document.write( "\n" ); document.write( "3x/2 = 3
\n" ); document.write( "Multiply both sides by 2
\n" ); document.write( " 3x = 6
\n" ); document.write( " x = 6/3
\n" ); document.write( " x = 2\r
\n" ); document.write( "\n" ); document.write( "To check you can always put the answers
\n" ); document.write( "back into the original equations:-
\n" ); document.write( "3x - 5 = 7
\n" ); document.write( "3*4 - 5 = 7
\n" ); document.write( "12 - 5 = 7 which is correct
\n" ); document.write( "3x/2 = 3
\n" ); document.write( "3*2/2 = 3
\n" ); document.write( "6/2 = 3 which is correct.
\n" ); document.write( "Hope this helps
\n" ); document.write( ":-)
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