document.write( "Question 753589: Given log 2=.3010 and log 3=.4771, evaluate log 6
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document.write( "Can you multiply the logs to get the value of log 6, so log 2 × log 3
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document.write( ".3010×.4771=.14361
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document.write( "Log 6=.14361 ? \n" );
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Algebra.Com's Answer #458487 by MathTherapy(10552)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Given log 2=.3010 and log 3=.4771, evaluate log 6 \n" ); document.write( "Can you multiply the logs to get the value of log 6, so log 2 × log 3 \n" ); document.write( ".3010×.4771=.14361 \n" ); document.write( "Log 6=.14361 ?\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "No, you cannot!!\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "You are correct that log 6 = log(2 * 3)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "However, log (2 * 3) = log 2 + log 3, which calculates to: .301 + .4771, or \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "You can do the check!!\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Send comments and “thank-yous” to “D” at MathMadEzy@aol.com \n" ); document.write( " |