document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=753467>Question 753467</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find x rounded to one decimal point. assume a=6\r<BR>\n" );
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document.write( "Picture of triangle below\r<BR>\n" );
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document.write( "http://www.webassign.net/sprecalc6/6-2-044-alt.gif </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #458397 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39617)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=458397\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The picture shows enough information to indicate the smaller right triangle.  a is the longer leg of this small triangle and x is the hypotenuse of this small triangle.\r<BR>\n" );
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document.write( "Although I do not remember the official theorem, this smaller right triangle is also a 30-60-90 right triangle, similar to the main right triangle.\r<BR>\n" );
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document.write( "The other leg of this small right triangle is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%2F2 ALIGN=MIDDLE  ALT=\"x%2F2\"   DISABLED_style= \"max-width:90%; height:auto;\" > in length.  <BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=a%5E2%2B%28x%2F2%29%5E2=x%5E2 ALIGN=MIDDLE  ALT=\"a%5E2%2B%28x%2F2%29%5E2=x%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" > directly according to pythagorean theorem<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%5E2%2F4-x%5E2=-a%5E2 ALIGN=MIDDLE  ALT=\"x%5E2%2F4-x%5E2=-a%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%5E2-x%5E2%2F4=a%5E2 ALIGN=MIDDLE  ALT=\"x%5E2-x%5E2%2F4=a%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%281-1%2F4%29x%5E2=a%5E2 ALIGN=MIDDLE  ALT=\"%281-1%2F4%29x%5E2=a%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%5E2=%284%2F3%29a%5E2 ALIGN=MIDDLE  ALT=\"x%5E2=%284%2F3%29a%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x=2a%2Fsqrt%283%29 ALIGN=MIDDLE  ALT=\"x=2a%2Fsqrt%283%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight%28x=%282%2F3%29a%2Asqrt%283%29%29 ALIGN=MIDDLE  ALT=\"highlight%28x=%282%2F3%29a%2Asqrt%283%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > and you can substitute a=6 and evaluate x. </SPAN>\n" );
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