document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=6918>Question 6918</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Ajax High School is putting a fence around the football field. The distance between the field and the fence is going to be 60 feet on end zone side and 45 feet on the sideline.  How many feet of fence will be needed? The football field measures 360 ft by 150 ft.  Do I use P=2l+2w (720+300)? and what does the distance between field and fence have to do with the problem?  Thanks, Sandy </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #458392 by </B><A HREF=/tutors/aboutme.mpl?userid=youngd><B>youngd(1)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=youngd><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=458392\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> bonster(299)'s answer is incorrect.\r<BR>\n" );
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document.write( "The field is 360 feet long  by 150 feet wide, and the fence is being placed 60 feet from EACH end zone and 45 from EACH sideline.  Therefore, the solution is;\r<BR>\n" );
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document.write( "P=l+w+l+w or 2l +2w\r<BR>\n" );
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document.write( "P=(60+360+60)+(45+150+45)+(60+360+60)+(45+150+45)<BR>\n" );
document.write( "P = 2*(480)+ 2*(240)<BR>\n" );
document.write( "P = 960 + 480<BR>\n" );
document.write( "P = 1440\r<BR>\n" );
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document.write( "1440 feet of fence will be needed.\r<BR>\n" );
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document.write( "The key is adding the additional fence on both ends. </SPAN>\n" );
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