document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=753095>Question 753095</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how would you solve y^2-x+2y+3=0 i am lost and do not know how to do it nor graph it.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #458376 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=458376\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> solve y^2-x+2y+3=0 <BR>\n" );
document.write( "complete the square:<BR>\n" );
document.write( "(y^2+2y+1)-1-x+3=0<BR>\n" );
document.write( "(y+1)^2=x-2<BR>\n" );
document.write( "This is an equation of a parabola that opens rightward with vertex at (2,-1)<BR>\n" );
document.write( "Its basic equation: (y-k)^2=4p(y-k), (h,k)=(x,y) coordinates of the vertex<BR>\n" );
document.write( "see graph below:\r<BR>\n" );
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