document.write( "Question 753292: i need help finding the center, coverticies, focis of this equation (x+1)^2/16-(y-2)^2/49=1 h=? k=? a=? b=? c=? \n" ); document.write( "

Algebra.Com's Answer #458362 by lwsshak3(11628) $\"\"$ $\"About$

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finding the center, coverticies, focis of this equation:
\n" ); document.write( "(x+1)^2/16-(y-2)^2/49=1 h=? k=? a=? b=? c=?
\n" ); document.write( "(x+1)^2/16-(y-2)^2/49=1
\n" ); document.write( "This is a hyperbola with horizontal transverse axis>
\n" ); document.write( "Its standard form of equation: $\"%28x-h%29%5E2%2Fa%5E2-%28y-k%29%5E2%2Fb%5E2=1\"$ , (a,b)=(x,y) coordinates of center
\n" ); document.write( "For given equation:
\n" ); document.write( "center: (-1,2)
\n" ); document.write( "a^2=16
\n" ); document.write( "a=4
\n" ); document.write( "b^2=49
\n" ); document.write( "b=7
\n" ); document.write( "co-vertices:(-1,2±b)=(-1,2±7‚=(-1,9) and (-1,-5)
\n" ); document.write( "c^2=a^2+b^2=16+49=65
\n" ); document.write( "c=√65≈8.06
\n" ); document.write( "foci::(-1,2±c)=(-1,2±8.06‚=(-1,10.06) and (-1,-6.06) \n" ); document.write( "

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