document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=753330>Question 753330</A>: <I><SPAN STYLE=\"word-break: break-all;\">  I need help on this distance problem; I am pretty sure that the formula is D1=K+D2 but I am not sure about what to do after that here is the problem; Amy had a 120 mile head start on Kathy. Kathy drove at 15 miles per hour, and Amy ran at 3 miles per hour. How far did Kathy have to drive to catch Amy. If you could help me with this problem I would really appreciate it. Thank You <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #458347 by </B><A HREF=/tutors/aboutme.mpl?userid=solver91311><B>solver91311(24713)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=solver91311><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=solver91311><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=458347\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <font face=\"Times New Roman\" size=\"+2\">\r<BR>\n" );
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document.write( "Think about it this way.  If A has a head start over K and they are going the exact same rate, then K never catches A.  But if K is going a little bit faster, then that little bit is used to eat up the head start and eventually K catches A.  In your problem, you have K going 12 miles per hour <i>faster</i> than A (15 minus 3 = 12), so it is this <i>difference</i> that is applied to the head start distance. How long does it take K to cover the 120 mile head start at 12 mph?\r<BR>\n" );
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document.write( "John<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE e^{i\pi}\ +\ 1\ =\ 0\"><BR>\n" );
document.write( "<font face=\"Math1\" size=\"+2\">Egw to Beta kai to Sigma</font><BR>\n" );
document.write( "My calculator said it, I believe it, that settles it<BR>\n" );
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