document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=753341>Question 753341</A>: <I><SPAN STYLE=\"word-break: break-all;\"> write an equation for a graph that is the set of all points in the plane that are equidistant from the given point and the given line.\r<BR>\n" );
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document.write( "F(-3,0), x=3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #458330 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=458330\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> write an equation for a graph that is the set of all points in the plane that are equidistant from the given point and the given line. <BR>\n" );
document.write( "F(-3,0), x=3<BR>\n" );
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document.write( "Every point on the line x = 3 has form (3,y)<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "Let the points equidistant from (-3,0) and (3,y) be (x,y)<BR>\n" );
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document.write( "distance = distance<BR>\n" );
document.write( "(x+3)^2 + y^2 = (x-3)^2<BR>\n" );
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document.write( "x^2 + 6x + 9 + y^2 = x^2 - 6x + 9<BR>\n" );
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document.write( "6x + y^2 = -6x<BR>\n" );
document.write( "12x = -y^2<BR>\n" );
document.write( "---<BR>\n" );
document.write( "x = (-1/12)y^2<BR>\n" );
document.write( "====================== </SPAN>\n" );
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