document.write( "Question 753277: The width and the length of a rectangle are consecutive even integers. If the width is decreased by 3 inches, then the area of the resulting rectangle is 24 square inches. What is the area of the original rectangle?
\n" ); document.write( "12 in^2
\n" ); document.write( "48 in^2
\n" ); document.write( "96 in^2
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Algebra.Com's Answer #458314 by MathTherapy(10552)\"\" \"About 
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\n" ); document.write( "The width and the length of a rectangle are consecutive even integers. If the width is decreased by 3 inches, then the area of the resulting rectangle is 24 square inches. What is the area of the original rectangle?
\n" ); document.write( "12 in^2
\n" ); document.write( "48 in^2
\n" ); document.write( "96 in^2\r
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\n" ); document.write( "\n" ); document.write( "Let the width be the smaller integer of W
\n" ); document.write( "Then length = W + 2\r
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\n" ); document.write( "\n" ); document.write( "If width is decreased by 3, it becomes: W - 3
\n" ); document.write( "Therefore, new width, times original length, equals given area, OR\r
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\n" ); document.write( "\n" ); document.write( "(W - 3)(W + 2) = 24\r
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\n" ); document.write( "\n" ); document.write( "\"W%5E2+-+W+-+6+=+24\"\r
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\n" ); document.write( "\n" ); document.write( "\"W%5E2+-+W+-+6+-+24+=+0\"\r
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\n" ); document.write( "\n" ); document.write( "\"W%5E2+-+W+-+30+=+0\"\r
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\n" ); document.write( "\n" ); document.write( "(W + 5)(W - 6) = 0\r
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\n" ); document.write( "\n" ); document.write( "W, or width = - 5(ignore), or 6\r
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\n" ); document.write( "\n" ); document.write( "Length, therefore = 8 (6 + 2)\r
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\n" ); document.write( "\n" ); document.write( "Area of original rectangle = 6 * 8, or \"highlight_green%2848_square_inches%29\"\r
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\n" ); document.write( "\n" ); document.write( "You can do the check!!\r
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\n" ); document.write( "\n" ); document.write( "Send comments and “thank-yous” to “D” at MathMadEzy@aol.com
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