document.write( "Question 753225: Graph the following function using the technique of shifting, compressing, strecthing and/or reflecting
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Algebra.Com's Answer #458283 by Edwin McCravy(20055) $\"\"$ $\"About$

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Graph the following function using the technique of shifting, compressing, strecthing and/or reflecting
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document.write( "g(x)=2√x-3 + 7\r\n" );
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document.write( "One important thing to remember in these problems is that \r\n" );
document.write( "we must shift vertically UP or DOWN last.\r\n" );
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document.write( "We start with\r\n" );
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document.write( "y = √x\r\n" );
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document.write( "Its domain is [0,)\r\n" );
document.write( "Its range is [0,)\r\n" );
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document.write( "Then we stretch it vertically by a factor of 2 by multiplying\r\n" );
document.write( "the right side by 2 and we get\r\n" );
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document.write( "y = 2√x\r\n" );
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document.write( "Its domain is [0,)\r\n" );
document.write( "Its range is [0,)\r\n" );
document.write( "Note that these did not change on this step\r\n" );
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document.write( "Then we shift it horizontally to the right by 3 units by \r\n" );
document.write( "replacing x by (x-3) in the right side and we get:\r\n" );
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document.write( "y = 2√x-3\r\n" );
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document.write( "Its domain is now [3,)\r\n" );
document.write( "Its range is [0,)\r\n" );
document.write( "Note that the domain shifted 3 to the right but\r\n" );
document.write( "the range did not change on this step.\r\n" );
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document.write( "Then finally we shift it vertically up by 7 units by adding 7 \r\n" );
document.write( "to the right side.:\r\n" );
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document.write( "y = 2√x-3 + 7\r\n" );
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document.write( "And that is the graph of\r\n" );
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document.write( "g(x) = 2√x-3 + 7\r\n" );
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document.write( "Its domain is [3,)\r\n" );
document.write( "Its range is [7,)\r\n" );
document.write( "Note that the domain did not change from the previous step,\r\n" );
document.write( "but the range shifted 7 units upward.\r\n" );
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document.write( "Edwin

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