document.write( "Question 753059: I've been stuck on this problem since Friday. Help please. \r
\n" ); document.write( "\n" ); document.write( "The length of a rectangle is 4 inches shorter than twice the width. If the perimeter of the rectangle is 34 inches, find the length and the width of the triangle.\r
\n" ); document.write( "\n" ); document.write( "The answer on the paper is L=10 W=7
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Algebra.Com's Answer #458198 by DrBeeee(684)\"\" \"About 
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Let W = the width of the rectangle
\n" ); document.write( "Let L = the length of the rectangle
\n" ); document.write( "The problem most of my students have is to remember the formula for the perimeter, p. It is
\n" ); document.write( "(1) p = 2*L + 2*W, do you have this?
\n" ); document.write( "Next write the expression for length as given by the problem statement, namely that the lenght is 4 less than twice the width or
\n" ); document.write( "(2) L = 2*W - 4. Do you have that?
\n" ); document.write( "Now put L of (2) into (1) and get
\n" ); document.write( "(3) p = 2*(2*W - 4) + 2*W
\n" ); document.write( "Now set (3) to the perimeter of 34 inches and get
\n" ); document.write( "(4) 2*(2*W - 4) + 2*W = 34
\n" ); document.write( "Now simplify (4) to obtain
\n" ); document.write( "(5) 4*W - 8 + 2*W = 34 or
\n" ); document.write( "(6) 6*W = 34 + 8 or
\n" ); document.write( "(7) 6*W = 42 or
\n" ); document.write( "(8) W = 42/6 or
\n" ); document.write( "(9) W = 7
\n" ); document.write( "Then from (1) we get
\n" ); document.write( "(10) L = 2*7 - 4 or
\n" ); document.write( "(11) L = 10
\n" ); document.write( "Let's check these values.
\n" ); document.write( "Is (2*10 + 2*7 = 34)?
\n" ); document.write( "Is (20 + 14 = 34)?
\n" ); document.write( "Is (34 = 34)? Yes
\n" ); document.write( "Answer: The lenght of the rectangle is 10 inches and the width is 7 inches.
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