document.write( "Question 65195: (x)^2+(1)^1=(x)^2 \n" ); document.write( "

Algebra.Com's Answer #45813 by funmath(2933) $\"\"$ $\"About$

You can put this solution on YOUR website!
(x)^2+(1)^1=(x)^2
\n" ); document.write( "This one has no solution, are you sure you copied it right?
\n" ); document.write( " $\"x%5E2%2B1%5E2=x%5E2\"$
\n" ); document.write( " $\"x%5E2%2B1=x%5E2\"$
\n" ); document.write( " $\"x%5E2-x%5E2%2B1=x%5E2-x%5E2\"$
\n" ); document.write( " $\"0%2B1=0\"$
\n" ); document.write( " $\"1=0\"$ Not true, your variables were eliminated, so there is no solution.
\n" ); document.write( ":
\n" ); document.write( "Since this was listed under pythagorean theorem, it's possible that you were just supposed to determine if the triangle was a right triangle. If you set this up right, it's not.
\n" ); document.write( "Another possibility is that you have your hypotenuse on the wrog side of the = sign. $\"a%5E2%2Bb%5E2=c%5E2\"$ , it doesn't matter which legs you pick for a and b, but you have to pick the hypotenuse for c. The hypotenuse is the side opposite the right angle that is usually signalled with a box in the corner. If c=1, this is solvable:
\n" ); document.write( " $\"x%5E2%2Bx%5E2=1%5E2\"$
\n" ); document.write( " $\"2x%5E2=1\"$
\n" ); document.write( " $\"2x%5E2%2F2=1%2F2\"$
\n" ); document.write( " $\"x=%2B-sqrt%281%2F2%29\"$ You can ignore the negative value in this case because you can't have a negative side of a triangle.
\n" ); document.write( " $\"x=sqrt%281%2F2%29\"$
\n" ); document.write( " $\"x=sqrt%281%2A2%2F%282%2A2%29%29\"$
\n" ); document.write( " $\"x=sqrt%282%2F4%29\"$
\n" ); document.write( " $\"x=sqrt%282%29%2Fsqrt%284%29\"$
\n" ); document.write( " $\"x=sqrt%282%29%2F2\"$
\n" ); document.write( "Happy Calculating!!! \n" ); document.write( "

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