document.write( "Question 752931: Hello, I am stuck on this word problem and was hoping you could help me out here.
\n" ); document.write( "I am usually pretty good with these sorts of problems, but I cannot get the formula to work right here.\r
\n" ); document.write( "\n" ); document.write( "Of the 65 students going on the soccer trip, 43 are players and 12 are left-handed. Only 5 of the left-handed students are soccer players. What is the probability that one of the students on the trip is a soccer player or is left-handed.
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Algebra.Com's Answer #458124 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
P(Soccer Player OR Left Handed) = P(Soccer Player) + P(Left Handed) - P(Soccer Player AND Left Handed)\r
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\n" ); document.write( "\n" ); document.write( "P(Soccer Player OR Left Handed) = 43/65 + 12/65 - 5/65\r
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\n" ); document.write( "\n" ); document.write( "P(Soccer Player OR Left Handed) = (43 + 12 - 5)/65\r
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\n" ); document.write( "\n" ); document.write( "P(Soccer Player OR Left Handed) = 50/65\r
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\n" ); document.write( "\n" ); document.write( "P(Soccer Player OR Left Handed) = 10/13 <---- Probability as a fraction\r
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\n" ); document.write( "\n" ); document.write( "P(Soccer Player OR Left Handed) = 0.769230769 <---- Probability as a decimal
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