document.write( "Question 752791: two swimmers swim towards each other with constant velocity,they meet each other at 50 km from east ,turn around & go to their respective ends and meet again at 20km from west.what is the total length of pool? \n" ); document.write( "
Algebra.Com's Answer #458102 by ankor@dixie-net.com(22740) You can put this solution on YOUR website! You must mean meters not km here. \n" ); document.write( ": \n" ); document.write( "two swimmers swim towards each other with constant velocity, \n" ); document.write( "they meet each other at 50 m from east, turn around & go to \n" ); document.write( " their respective ends and meet again at 20 m from west. \n" ); document.write( "what is the total length of pool? \n" ); document.write( ": \n" ); document.write( "Let x = the length of the pool \n" ); document.write( ": \n" ); document.write( "Their first meeting \n" ); document.write( "1st swimmer travels 50 m east \n" ); document.write( "2nd swimmer travels (x-50) m from the west \n" ); document.write( ": \n" ); document.write( "Their second meeting \n" ); document.write( "1st swimmer travels (x-50) + 20 = (x-30) \n" ); document.write( "2nd swimmer travels 50 + (x-20) = (x+30) \n" ); document.write( ": \n" ); document.write( "The ratio of the distances of the swimmers is the same for each scenario \n" ); document.write( " \n" ); document.write( "cross multiply \n" ); document.write( "50(x+30) = (x-50)(x-30) \n" ); document.write( "FOIL \n" ); document.write( "50x + 1500 = x^2 - 30x - 50x + 1500 \n" ); document.write( "50x + 1500 = x^2 - 80x + 1500 \n" ); document.write( "subtract 1500 from both sides \n" ); document.write( "50x = x^2 - 80x \n" ); document.write( "0 = x^2 - 80x - 50x \n" ); document.write( "x^2 - 130x = 0 \n" ); document.write( "x^2 = 130x \n" ); document.write( "divide both sides by x \n" ); document.write( "x = 130 meters is the length of the pool \n" ); document.write( " |