document.write( "Question 752836: Mr. Nelson lost one of his student's test papers. He knows that the other 4 students scored as follows: 93, 86, 86, 84. He also knows that the average score is 88.2. What is the score on the missing paper?
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Algebra.Com's Answer #458073 by Okeke_Christian(26)\"\" \"About 
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Let the score on the missing paper be x.
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\n" ); document.write( "If he lost score of 1 student and has score of other 4, it means he has a total of 5 students!\r
\n" ); document.write( "\n" ); document.write( "Mean (Average) = Total Score / Number of Students.\r
\n" ); document.write( "\n" ); document.write( "We have,
\n" ); document.write( "Mean (Average) = 88.2 = 882/10;
\n" ); document.write( "Total Score = (93+86+86+84)+ x = 349+x
\n" ); document.write( "Number of Students = 5;\r
\n" ); document.write( "\n" ); document.write( "\"%28882%2F10%29+=+%28349%2Bx%29%2F5\"\r
\n" ); document.write( "\n" ); document.write( "Cross Multiply
\n" ); document.write( "\"%28882%2A5%29=10%2A%28349%2Bx%29\"
\n" ); document.write( "\"4410=3490%2B10x\"
\n" ); document.write( "\"4410-3490=10x\"
\n" ); document.write( "\"920=10x\"
\n" ); document.write( "Divide through by 10:
\n" ); document.write( "\"%28920%2F10%29=%2810x%2F10%29\"
\n" ); document.write( "\"92=x\"\r
\n" ); document.write( "\n" ); document.write( "Therefore, missing score is 92\r
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