document.write( "Question 752836: Mr. Nelson lost one of his student's test papers. He knows that the other 4 students scored as follows: 93, 86, 86, 84. He also knows that the average score is 88.2. What is the score on the missing paper?
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Algebra.Com's Answer #458073 by Okeke_Christian(26)![]() ![]() You can put this solution on YOUR website! Let the score on the missing paper be x. \n" ); document.write( " \n" ); document.write( "If he lost score of 1 student and has score of other 4, it means he has a total of 5 students!\r \n" ); document.write( "\n" ); document.write( "Mean (Average) = Total Score / Number of Students.\r \n" ); document.write( "\n" ); document.write( "We have, \n" ); document.write( "Mean (Average) = 88.2 = 882/10; \n" ); document.write( "Total Score = (93+86+86+84)+ x = 349+x \n" ); document.write( "Number of Students = 5;\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Cross Multiply \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Divide through by 10: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Therefore, missing score is 92\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |