document.write( "Question 752813: If the numerator of a fraction is increased by 200% and the denominator is increased by 300% the
\n" ); document.write( "Resultant fraction is 6/11. What was the original fraction?
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Algebra.Com's Answer #458061 by dkppathak(439)\"\" \"About 
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let fraction is x/y
\n" ); document.write( "when numerator increase by 200%
\n" ); document.write( "means numerator will be x+2x =3x
\n" ); document.write( "and denominator increased by 300% means denominator will be y = 3y =4y
\n" ); document.write( "new fraction will be 3x/4y =6/66 (given)
\n" ); document.write( "we can say
\n" ); document.write( "3x/4y = 6/11
\n" ); document.write( "dividing numerator by 3 and denominator by 4 both side we will get
\n" ); document.write( "x/y =6/3/11/4
\n" ); document.write( "x/y=6x4/11x3
\n" ); document.write( "x/y =24/33
\n" ); document.write( "x/y =8/11
\n" ); document.write( "answer
\n" ); document.write( "fraction will be 8/11
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