document.write( "Question 752729: A train has a regularly scheduled run between two towns. If the train travels at 40 mph, then it arrives at its destination 10 minutes late. If the train travels at 30 mph, then it is 16 minutes late. Find the distance between the two towns. \n" ); document.write( "
Algebra.Com's Answer #458024 by MathTherapy(10552)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "A train has a regularly scheduled run between two towns. If the train travels at 40 mph, then it arrives at its destination 10 minutes late. If the train travels at 30 mph, then it is 16 minutes late. Find the distance between the two towns.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Let distance be D \n" ); document.write( "Then time taken at 40 mph = \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Time to get there on time = \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Time taken at 30 mph = \n" ); document.write( "Time to get there on time = \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Therefore, we have: \n" ); document.write( "3D – 20 = 2(2D – 16) ------- Multiplying by LCD, 120 \n" ); document.write( "3D – 20 = 4D – 32 \n" ); document.write( "3D – 4D = - 32 + 20 \n" ); document.write( "- D = - 12\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "D, or distance between the towns = \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "You can do the check!!\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Send comments and “thank-yous” to “D” at MathMadEzy@aol.com \n" ); document.write( " |