document.write( "Question 752709: X/1 2 3 4 5 6
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document.write( "F/4 6 a 10 b 8
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document.write( "The mean of 50 observations for a grouped data is 3.72 the two frequencies are missing in the frequency table.find the missing frequencies..
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Algebra.Com's Answer #458020 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! X/1 2 3 4 5 6 \n" ); document.write( "F/4 6 a 10 b 8 \n" ); document.write( "The mean of 50 observations for a grouped data is 3.72 the two frequencies are missing in the frequency table.find the missing frequencies.. \n" ); document.write( "------ \n" ); document.write( "mean = [1*4+2*6+3a+4*10+5b+6*8]/50 \n" ); document.write( "[4+12+3a+40+5b+48]/50 = 3.72 \n" ); document.write( "----- \n" ); document.write( "[3a+5b+104] = 186 \n" ); document.write( "3a+5b = 82 \n" ); document.write( "================================ \n" ); document.write( "Sum of the frequencies = 50 \n" ); document.write( "a+b + 28 = 50 \n" ); document.write( "================================== \n" ); document.write( "Using the 2 equations, solve for \"a\" and for \"b\": \n" ); document.write( "3a+5b = 82 \n" ); document.write( "a + b = 22 \n" ); document.write( "-------- \n" ); document.write( "Modify for elimination: \n" ); document.write( "3a + 5b = 82 \n" ); document.write( "3a + 3b = 66 \n" ); document.write( "---- \n" ); document.write( "Subtract and solve for \"b\": \n" ); document.write( "2b = 16 \n" ); document.write( "b = 8 \n" ); document.write( "----- \n" ); document.write( "Solve for \"a\": \n" ); document.write( "a + 8 = 22 \n" ); document.write( "a = 14 \n" ); document.write( "========================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "========================== \n" ); document.write( " \n" ); document.write( " |