document.write( "Question 752709: X/1 2 3 4 5 6
\n" ); document.write( "F/4 6 a 10 b 8
\n" ); document.write( "The mean of 50 observations for a grouped data is 3.72 the two frequencies are missing in the frequency table.find the missing frequencies..
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Algebra.Com's Answer #458020 by stanbon(75887)\"\" \"About 
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X/1 2 3 4 5 6
\n" ); document.write( "F/4 6 a 10 b 8
\n" ); document.write( "The mean of 50 observations for a grouped data is 3.72 the two frequencies are missing in the frequency table.find the missing frequencies..
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\n" ); document.write( "mean = [1*4+2*6+3a+4*10+5b+6*8]/50
\n" ); document.write( "[4+12+3a+40+5b+48]/50 = 3.72
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\n" ); document.write( "[3a+5b+104] = 186
\n" ); document.write( "3a+5b = 82
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\n" ); document.write( "Sum of the frequencies = 50
\n" ); document.write( "a+b + 28 = 50
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\n" ); document.write( "Using the 2 equations, solve for \"a\" and for \"b\":
\n" ); document.write( "3a+5b = 82
\n" ); document.write( "a + b = 22
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\n" ); document.write( "Modify for elimination:
\n" ); document.write( "3a + 5b = 82
\n" ); document.write( "3a + 3b = 66
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\n" ); document.write( "Subtract and solve for \"b\":
\n" ); document.write( "2b = 16
\n" ); document.write( "b = 8
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\n" ); document.write( "Solve for \"a\":
\n" ); document.write( "a + 8 = 22
\n" ); document.write( "a = 14
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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