document.write( "Question 752582: Determine the equation of the line with slope -2/3 and passes through the point (-6, 3).\r
\n" ); document.write( "\n" ); document.write( "Express the equation of the line in both slope–intercept form and standard form.
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Algebra.Com's Answer #458018 by ankor@dixie-net.com(22740)\"\" \"About 
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Determine the equation of the line with slope -2/3 and passes through
\n" ); document.write( " the point (-6, 3).
\n" ); document.write( "Express the equation of the line in both slope–intercept form
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\n" ); document.write( "Use the point point/slope formula: y - y1 = m(x - x1)
\n" ); document.write( "y - 3 = \"-2%2F3\"(x - (-6))
\n" ); document.write( "y - 3 = \"-2%2F3\"(x + 6)
\n" ); document.write( "y - 3 = \"-2%2F3\"x - 4
\n" ); document.write( "y = \"-2%2F3\"x - 4 + 3
\n" ); document.write( "y = \"-2%2F3\"x - 1; the slope/intercept form
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\n" ); document.write( "Find the standard form
\n" ); document.write( "y = \"-2%2F3\"x - 1
\n" ); document.write( "\"2%2F3\"x + y - 1
\n" ); document.write( "get rid of the denominator, mult by 3, resulting in:
\n" ); document.write( "2x + 3y = -3
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\n" ); document.write( "Check solutions by replacing x and y with -6 and 3
\n" ); document.write( "2(-6) + 3(3) = -3
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