document.write( "Question 64833This question is from textbook An Incremental Development
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\n" ); document.write( "\n" ); document.write( "(-x + 2 / 3) - (2x + 5 / 4) = 5\r
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Algebra.Com's Answer #45800 by praseenakos@yahoo.com(507)\"\" \"About 
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QUESTION:\r
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\n" ); document.write( "\n" ); document.write( "(-x + 2 / 3) - (2x + 5 / 4) = 5\r
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\n" ); document.write( "\n" ); document.write( " -x + 2/3 - 2x - 5/4 = 5\r
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\n" ); document.write( "\n" ); document.write( "-x -2x +2/3 - 5/4 =5\r
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\n" ); document.write( "\n" ); document.write( "==> (-x -2x )+ (2/3 - 5/4) =5\r
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\n" ); document.write( "\n" ); document.write( "==> -3x + (2*4 - 5*3)/12 = 5\r
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\n" ); document.write( "\n" ); document.write( "==> -3x + (8 - 15 )/12 = 5\r
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\n" ); document.write( "\n" ); document.write( "==> -3x -7/12 = 5\r
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\n" ); document.write( "\n" ); document.write( "==> -3x = 5 +7/12\r
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\n" ); document.write( "\n" ); document.write( "==> -3x = (5*12+7)/12\r
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\n" ); document.write( "\n" ); document.write( "==> -3x = ( 60 +7)/12\r
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\n" ); document.write( "\n" ); document.write( "==> -3x = 67/12\r
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\n" ); document.write( "\n" ); document.write( "==> x = -67/(3*12)\r
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\n" ); document.write( "\n" ); document.write( "==> x = -67/36\r
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\n" ); document.write( "\n" ); document.write( " x = -67/36\r
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