document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=752741>Question 752741</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve for the root(s) of Sqrt(x^2+7)= -sqrt(2)x+1 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #457993 by </B><A HREF=/tutors/aboutme.mpl?userid=malglu><B>malglu(63)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=malglu><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=457993\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> square both sides and yo get<BR>\n" );
document.write( "x^2 +7 = -(2x+1)<BR>\n" );
document.write( "multiply out and move all terms over to one side\r<BR>\n" );
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document.write( "x^2 +2x +8 = 0\r<BR>\n" );
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document.write( "use the formula to get the roots\r<BR>\n" );
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document.write( "-1 + or - sqrt -7 all divided by 2\r<BR>\n" );
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document.write( "sqrt -7 is all kown as i sqrt 7 </SPAN>\n" );
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