document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=747534>Question 747534</A>: <I><SPAN STYLE=\"word-break: break-all;\"> please help me to solve this problem. <BR>\n" );
document.write( "The absolute value of 2x is less than or equal to the absolute of x-3<BR>\n" );
document.write( "|2x|<=|x-3| </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #457979 by </B><A HREF=/tutors/aboutme.mpl?userid=tommyt3rd><B>tommyt3rd(5050)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=tommyt3rd><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=tommyt3rd><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=457979\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> We start by finding points from which we will find the boundaries for the intervals\r<BR>\n" );
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document.write( "2x=x-3 or 2x=-x+3<BR>\n" );
document.write( "x=-3  or x=1\r<BR>\n" );
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document.write( "Next we test all intervals\r<BR>\n" );
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document.write( "On  x<-3  we test x=-4 and see 8<7 (false)\r<BR>\n" );
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document.write( "On -3<x<1 we test x=0 and see 0<3 (true)\r<BR>\n" );
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document.write( "On x>1 we test x=2 and see 4<1 (false)\r<BR>\n" );
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document.write( "Our solution interval: [-3,1]\r<BR>\n" );
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document.write( ":) </SPAN>\n" );
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