document.write( "Question 752687: Find the dimensions of a rectangle whose area is 216 cm2 and whose perimeter is 60 cm \n" ); document.write( "

Algebra.Com's Answer #457962 by tommyt3rd(5050) $\"\"$ $\"About$

You can put this solution on YOUR website!
$\"l%2Aw=216\"$ \r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " $\"2%28l%2Bw%29=60\"$ therefore $\"l%2Bw=30\"$ \r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " $\"l%2830-l%29=216\"$ \r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " $\"l%5E2-30%2Al%2B216=0\"$ \r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "l=12 or l=18\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "so l=12 and w=18\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( ":) \n" ); document.write( "

\n" );