document.write( "Question 65262: I am having difficulty with this question....
\n" ); document.write( "I have to find the x intercept of y=x^3-2x^2-8x\r
\n" ); document.write( "\n" ); document.write( "and log x+log(x+1)=log 12\r
\n" ); document.write( "\n" ); document.write( "can someone please help me..
\n" ); document.write( "

Algebra.Com's Answer #45793 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
I have to find the x intercept of y=x^3-2x^2-8x
\n" ); document.write( "Let y=0
\n" ); document.write( "Then x^3-2x^2-8x=0
\n" ); document.write( "x(x^2-2x-8)=0
\n" ); document.write( "x(x-4)(x+2)=
\n" ); document.write( "x=0 or x=4 or x=-2
\n" ); document.write( "-----------------------------
\n" ); document.write( "and log x+log(x+1)=log 12
\n" ); document.write( "log[x(x+1)] = log(12)
\n" ); document.write( "x(x+1)=12
\n" ); document.write( "x^2+x-12=0
\n" ); document.write( "(x+4)(x-3)=0
\n" ); document.write( "x=3
\n" ); document.write( "X cannot be -4 in the original equation.
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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