document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=752631>Question 752631</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve the equation log3(x)-log3(x-5)=1\r<BR>\n" );
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document.write( "I tried like this:\r<BR>\n" );
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document.write( "log3(x/x-5)=1<BR>\n" );
document.write( "3=(x/x-5)<BR>\n" );
document.write( "3*(x-5)=x<BR>\n" );
document.write( "3x-15=x<BR>\n" );
document.write( "2x=15<BR>\n" );
document.write( "x=15/2\r<BR>\n" );
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document.write( "but the answer should be x=5/4, where did I go wrong? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #457920 by </B><A HREF=/tutors/aboutme.mpl?userid=dkppathak><B>dkppathak(439)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=dkppathak><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=dkppathak><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=457920\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> yes you are correct for your solution<BR>\n" );
document.write( "log (base3)x-log (base3)x-5=1<BR>\n" );
document.write( "by using log formula <BR>\n" );
document.write( "we can do as log (base3)x/x-5 =1<BR>\n" );
document.write( "we can do it as<BR>\n" );
document.write( "3 to the power 1= x/x-5<BR>\n" );
document.write( "3=x/x-5<BR>\n" );
document.write( "3x-15=x<BR>\n" );
document.write( "3x-x =15<BR>\n" );
document.write( "2x=15<BR>\n" );
document.write( "x=15/2<BR>\n" );
document.write( "x=7.5<BR>\n" );
document.write( " </SPAN>\n" );
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