document.write( "Question 752614: Find z, if the probability that a random variable having the standard normal distribution will take on a value.
\n" ); document.write( "(i) less than z is 0.9911
\n" ); document.write( "(ii) greater than z is 0.1093
\n" ); document.write( "(iii) beteen -z and z is 0.9298 \n" ); document.write( "
Algebra.Com's Answer #457917 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
Find z, if the probability that a random variable having the standard normal distribution will take on a value.
\n" ); document.write( "------------
\n" ); document.write( "Using a TI-84:
\n" ); document.write( "(i) less than z is 0.9911 = invNorm(0.9911) = 2.3698
\n" ); document.write( "---------------------------------
\n" ); document.write( "(ii) greater than z is 0.1093 = normalcdf(0.1093,100) = 0.4565
\n" ); document.write( "---------------------------------
\n" ); document.write( "(iii) beteen -z and z is 0.9298
\n" ); document.write( "Draw the picture on a standard normal curve.
\n" ); document.write( "---
\n" ); document.write( "The area is split into two equal parts; each is (1/2)0.9298 = 0.4649
\n" ); document.write( "----
\n" ); document.write( "The left tail for -z is (0.5-0.4649) = 0.0351
\n" ); document.write( "That negative z-value is invNorm(0.0351) = -1.8106
\n" ); document.write( "z = +1.8106
\n" ); document.write( "=============================
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "===============
\n" ); document.write( " \r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "
\n" );