document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=752607>Question 752607</A>: <I><SPAN STYLE=\"word-break: break-all;\"> THE ALTITUDE OF RIGHT ANGLE TRIANGLE IS 7 cm LESS THAN ITS BASE.IF THE HYPOTENUSE IS 13 cm,FIND THE OTHER TWO SIDES<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #457902 by </B><A HREF=/tutors/aboutme.mpl?userid=dkppathak><B>dkppathak(439)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=dkppathak><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=dkppathak><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=457902\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let base of triangle is x cm<BR>\n" );
document.write( "altitude will be x-7<BR>\n" );
document.write( "hypotenuse =13 given<BR>\n" );
document.write( "H^2 =x^2+(x-7)2 by Pythagoras theorm<BR>\n" );
document.write( "13^2 =x^2 +(x-7)^2<BR>\n" );
document.write( "169=x^2+x^2+49-14x<BR>\n" );
document.write( "169=2x^2-14x+49<BR>\n" );
document.write( "2x^2-14x-120 =0<BR>\n" );
document.write( "x^2-7x-60<BR>\n" );
document.write( "by splitting  middle term<BR>\n" );
document.write( "x^2-12x+5x-60 =0<BR>\n" );
document.write( "(x-12)(x+5) =0<BR>\n" );
document.write( "x-12 =0 or x+5=0<BR>\n" );
document.write( "x=12 or x=-5<BR>\n" );
document.write( "neglecting negative value <BR>\n" );
document.write( "x=12 cm<BR>\n" );
document.write( "there for base is 12cm<BR>\n" );
document.write( "and altitude is 12-7 =5cm\r<BR>\n" );
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document.write( "ANSWER  base is 12 cm<BR>\n" );
document.write( "        altitude 5 cm  <BR>\n" );
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