document.write( "Question 752601: Find the vertices and asymptotes of the hyperbola. 9y^2 - 16x^2 = 144 \n" ); document.write( "
Algebra.Com's Answer #457894 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! Find the vertices and asymptotes of the hyperbola. \n" ); document.write( "9y^2-16x^2=144 \n" ); document.write( "y^2/16-x^2/9=1 \n" ); document.write( "This is a hyperbola with vertical transverse axis. \n" ); document.write( "Its standard form of equation: \n" ); document.write( "center(0,0) \n" ); document.write( "a^2=16 \n" ); document.write( "a=√16=4 \n" ); document.write( "vertices: (0, 0±a)=((), 0±4)=(0,-4) and (0,4) \n" ); document.write( "b^2=9 \n" ); document.write( "b=3 \n" ); document.write( ".. \n" ); document.write( "asymptotes: straight line equations of the form: y=mx+b, m=slope, b=y-intercept \n" ); document.write( "line goes thru center of hyperbola, y-intercept=0 \n" ); document.write( "slopes of asymptotes: ±a/b=±4/3 (for hyperbolas with vertical transverse axis) \n" ); document.write( "equation of asymptote with negative slope: y=-4x/3 \n" ); document.write( "equation of asymptote with positive slope: y=4x/3\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |