document.write( "Question 752570: A hardware store sells numerals for house number. It has large quantities of the numerals 3, 5, and 8 but no other numerals. How many different house numbers, with no more than 3 digits, can be made form those numerals?\r
\n" ); document.write( "\n" ); document.write( "A) 33
\n" ); document.write( "B)21
\n" ); document.write( "C)27
\n" ); document.write( "D)36
\n" ); document.write( "E)39\r
\n" ); document.write( "\n" ); document.write( "Thanks! \r
\n" ); document.write( "\n" ); document.write( "Well, so far I've worked out that you could have A =3 B= 5 and C=8, and then go a, aa, aaa, ab,abb,aab,ac,acc, aac, but I always get confused even when I write it down. Thanks for bothering to help me!
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Algebra.Com's Answer #457875 by FrankM(1040)\"\" \"About 
You can put this solution on YOUR website!
The 3 digit numbers total 3x3x3=27
\n" ); document.write( "The 2 digit numbers total 3x3 = 9
\n" ); document.write( "Last 3 single digit = 3 \r
\n" ); document.write( "\n" ); document.write( "39 total
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