document.write( "Question 752286: hello, can someone EXPLAIN how do figure out the following:\r
\n" ); document.write( "\n" ); document.write( "1/2sqrt5 + 1 1/2sqrt20 = 7/2sqrt5\r
\n" ); document.write( "\n" ); document.write( "I appreciate any help on the process. thank you!
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Algebra.Com's Answer #457858 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
Assume the problem is:
\n" ); document.write( "\"1%2F2\"\"sqrt%285%29\" + 1 \"1%2F2\"\"sqrt%2820%29\" = \"7%2F2\"\"sqrt%285%29\"
\n" ); document.write( "Make the 1 and 1/2 an improper fraction
\n" ); document.write( "\"1%2F2\"\"sqrt%285%29\" + \"3%2F2\"\"sqrt%2820%29\" = \"7%2F2\"\"sqrt%285%29\"
\n" ); document.write( "multiply the equation by 2, this gets rid of the denominators
\n" ); document.write( "\"sqrt%285%29\" + \"3%2Asqrt%2820%29\" = \"7%2Asqrt%285%29\"
\n" ); document.write( "Factor inside the middle radical to reveal a perfect square
\n" ); document.write( "\"sqrt%285%29\" + \"3%2Asqrt%284%2A5%29\" = \"7%2Asqrt%285%29\"
\n" ); document.write( "Extract the square root of 4
\n" ); document.write( "\"sqrt%285%29\" + \"3%2A2%2Asqrt%285%29\" = \"7%2Asqrt%285%29\"
\n" ); document.write( "\"sqrt%285%29\" + \"6%2Asqrt%285%29\" = \"7%2Asqrt%285%29\"
\n" ); document.write( "they are like terms now sqrt(5) just add
\n" ); document.write( "\"7%2Asqrt%285%29\" = \"7%2Asqrt%285%29\" which is obviously true
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