document.write( "Question 752567: how many gallons of 20% antifreeze should be mixed with 10 gallons of 83% antifreeze to obtain 55% antifreeze mixture? \n" ); document.write( "
Algebra.Com's Answer #457851 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
how many gallons of 20% antifreeze should be mixed with 10 gallons of 83% antifreeze to obtain 55% antifreeze mixture?
\n" ); document.write( "---------
\n" ); document.write( "Equation:
\n" ); document.write( "alcohol + alcohol = alcohol
\n" ); document.write( "0.20x + 0.83*10 = 0.55(x+10)
\n" ); document.write( "-----
\n" ); document.write( "20x + 83*10 = 55x + 55*10
\n" ); document.write( "----------
\n" ); document.write( "35x = 28*10
\n" ); document.write( "x = (2/7)28
\n" ); document.write( "x = 8 gallons (amt. of 20% solution needed)
\n" ); document.write( "==============================================
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "================
\n" ); document.write( "
\n" );