document.write( "Question 752567: how many gallons of 20% antifreeze should be mixed with 10 gallons of 83% antifreeze to obtain 55% antifreeze mixture? \n" ); document.write( "
Algebra.Com's Answer #457851 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! how many gallons of 20% antifreeze should be mixed with 10 gallons of 83% antifreeze to obtain 55% antifreeze mixture? \n" ); document.write( "--------- \n" ); document.write( "Equation: \n" ); document.write( "alcohol + alcohol = alcohol \n" ); document.write( "0.20x + 0.83*10 = 0.55(x+10) \n" ); document.write( "----- \n" ); document.write( "20x + 83*10 = 55x + 55*10 \n" ); document.write( "---------- \n" ); document.write( "35x = 28*10 \n" ); document.write( "x = (2/7)28 \n" ); document.write( "x = 8 gallons (amt. of 20% solution needed) \n" ); document.write( "============================================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "================ \n" ); document.write( " |