document.write( "Question 752549: (15m+3)/(2)=-6
\n" ); document.write( "3/2x-15=-12
\n" ); document.write( "-7x+3=-15/2
\n" ); document.write( "4x+1/2(12x+2)=3
\n" ); document.write( "3/2(x+8)=6x
\n" ); document.write( "

Algebra.Com's Answer #457849 by josgarithmetic(39617)\"\" \"About 
You can put this solution on YOUR website!
Examening your work for any mistakes:\r
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\n" ); document.write( "\n" ); document.write( "(15x+3)/(2)=-6
\n" ); document.write( "3/2x-15=-12-------------the first mistake,
\n" ); document.write( "-7x+3=-15/2
\n" ); document.write( "4x+1/2(12x+2)=3
\n" ); document.write( "3/2(x+8)=6x\r
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\n" ); document.write( "\n" ); document.write( "What you could do:
\n" ); document.write( "MULTIPLY BOTH sides by 2;
\n" ); document.write( "Add the additive inverse of 3 to both sides;
\n" ); document.write( "Multiply the multiplicative inverse of 15 by both sides.
\n" ); document.write( "Simplify.
\n" ); document.write( "This is your answer.\r
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\n" ); document.write( "\n" ); document.write( "You basically want to undo everything that has been done to x in order to have prepared the original equation. I very obviously did not carry out the steps. I only stated what steps to perform.
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