document.write( "Question 752549: (15m+3)/(2)=-6
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document.write( "3/2x-15=-12
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document.write( "-7x+3=-15/2
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document.write( "4x+1/2(12x+2)=3
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document.write( "3/2(x+8)=6x \n" );
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Algebra.Com's Answer #457849 by josgarithmetic(39617)![]() ![]() ![]() You can put this solution on YOUR website! Examening your work for any mistakes:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(15x+3)/(2)=-6 \n" ); document.write( "3/2x-15=-12-------------the first mistake, \n" ); document.write( "-7x+3=-15/2 \n" ); document.write( "4x+1/2(12x+2)=3 \n" ); document.write( "3/2(x+8)=6x\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "What you could do: \n" ); document.write( "MULTIPLY BOTH sides by 2; \n" ); document.write( "Add the additive inverse of 3 to both sides; \n" ); document.write( "Multiply the multiplicative inverse of 15 by both sides. \n" ); document.write( "Simplify. \n" ); document.write( "This is your answer.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "You basically want to undo everything that has been done to x in order to have prepared the original equation. I very obviously did not carry out the steps. I only stated what steps to perform. \n" ); document.write( " |