document.write( "Question 752564: A line with a slope of -(1/2) crosses the X-axis at the point (4,0). At what point does it cross the Y-axis? (Hint: The unknown point has coordinates (0,y), where y is to be calculated. This point is the so-called y intercept.) \n" ); document.write( "

Algebra.Com's Answer #457844 by josgarithmetic(39620) $\"\"$ $\"About$

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You could use the point-slope form for a line.\r
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\n" ); document.write( "\n" ); document.write( "Instead, here is the use of slope-intercept form.\r
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\n" ); document.write( "\n" ); document.write( " $\"y=-%281%2F2%29x%2Bb\"$ , where b is the y intercept.
\n" ); document.write( "You were given the x intercept point of x=4 and y=0. Putting these into our equation gives us:
\n" ); document.write( " $\"0=-%281%2F2%29%2A4%2Bb\"$
\n" ); document.write( " $\"0=-2%2Bb\"$
\n" ); document.write( " $\"b=2\"$ .\r
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\n" ); document.write( "\n" ); document.write( "The equation desired then is $\"highlight%28y=-%281%2F2%29x%2B2%29\"$ \n" ); document.write( "

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