document.write( "Question 752562: The length of a rectangle is 6 inches more than its width. The area of the rectangle is 91 square inches.
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document.write( "Please tell how this is done thanks \n" );
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Algebra.Com's Answer #457841 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! The length of a rectangle is 6 inches more than its width. The area of the rectangle is 91 square inches. \n" ); document.write( "------------------- \n" ); document.write( "Let width be \"x\": \n" ); document.write( "Then length will be \"x+6\": \n" ); document.write( "--------------------- \n" ); document.write( "Equation: \n" ); document.write( "Area = length*width \n" ); document.write( "A(x) = x(x+6) = 91 \n" ); document.write( "x^2 + 6x - 91 = 0 \n" ); document.write( "---------------------- \n" ); document.write( "x^2 + 13x - 7x -91 = 0 \n" ); document.write( "x(x+13)-7(x+13) = 0 \n" ); document.write( "(x+13)(x-7) = 0 \n" ); document.write( "Positive solution: \n" ); document.write( "x = 7 inches (width) \n" ); document.write( "x+6 = 13 inches (length) \n" ); document.write( "================= \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "====================== \n" ); document.write( " \n" ); document.write( " |