document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=752492>Question 752492</A>: <I><SPAN STYLE=\"word-break: break-all;\"> \r<BR>\n" );
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document.write( "find the dimensions of a rectangle whose length is 50 inches more than its width and whose perimeter is 500 inches<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #457788 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley79><B>checkley79(3341)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley79><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=457788\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> P=2L+2W<BR>\n" );
document.write( "L=W+50<BR>\n" );
document.write( "500=2(W+50)+2W<BR>\n" );
document.write( "500=2W+100+2W<BR>\n" );
document.write( "4W=500-100<BR>\n" );
document.write( "4W=400<BR>\n" );
document.write( "W=400/4<BR>\n" );
document.write( "W=100 INCHES FOR THW WIDTH.<BR>\n" );
document.write( "L=100+50=150 INCHES FOR THE LENGTH.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "500=2*150+2*100<BR>\n" );
document.write( "500=300+200<BR>\n" );
document.write( "500=500 </SPAN>\n" );
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