document.write( "Question 65237: ok here is my super dooper hard question ok ready?
\n" ); document.write( "a bus company has 4000 pasangers daily, each paying a fait of 2 dollars. for each 0.15$ increase the company looses about 40 passangers. if the company needs to tske in $10450 per day to stay in buisness what fare should be changed?
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Algebra.Com's Answer #45775 by checkley71(8403)\"\" \"About 
You can put this solution on YOUR website!
THE EQUATION FOR THIS PROBLEM IS:
\n" ); document.write( "(4000-40X)(2+.15X)=10450
\n" ); document.write( "8000-80X+600X-6X^2=10450
\n" ); document.write( "6X^2-520X+2450=0
\n" ); document.write( "3X^2-260X+1225=0 USING THE QUADRATIC EQUATION TO SOLVE FOR X WE HAVE
\n" ); document.write( "X=(-B+-SQRT[B^2-4AC])/2A
\n" ); document.write( "X=(260+-SQRT[-260*-260-4*3*1225])/2*3
\n" ); document.write( "X=(260+-SQRT[67600-14700])/6
\n" ); document.write( "X=(260+-SQRT[52900])/6
\n" ); document.write( "X=(260+-230)/6
\n" ); document.write( "X=(260+230)/6
\n" ); document.write( "X=490/6
\n" ); document.write( "X=81.666666 SOLUTION
\n" ); document.write( "X=(260-230)/6
\n" ); document.write( "X=30/6
\n" ); document.write( "X=5 SOLUTION
\n" ); document.write( "PROOF
\n" ); document.write( "(4000-40*5)(2+.15*5)=10450
\n" ); document.write( "(4000-200)(2+.75)=10450
\n" ); document.write( "3800*2.75=10450
\n" ); document.write( "10450=10450
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\n" ); document.write( "MERRY CHRISTMAS
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