document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=752401>Question 752401</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi,\r<BR>\n" );
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document.write( "I am trying to simplify the equation  15x2y x –x3/3y\r<BR>\n" );
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document.write( "15x to the power of 2 then y multiplied by -x to the power of 3 divided by 3y\r<BR>\n" );
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document.write( "I am totally stumped\r<BR>\n" );
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document.write( "Thanks </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #457727 by </B><A HREF=/tutors/aboutme.mpl?userid=sajal02><B>sajal02(2)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=sajal02><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=457727\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 15x^2*y*(-x)^3/3y<BR>\n" );
document.write( "now it means here, we will solve power of negative sign so we get negative in starting , now we will divide 15 by 3 so we get 5 , again we will cancel y of numerator with y of denominatoran in last we will add powers of x so we get x^2+3, it means 2^5 , now after combining we get,-5x^5 ans </SPAN>\n" );
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