document.write( "Question 730715: Solve by any method - Addition or Substitution\r
\n" ); document.write( "\n" ); document.write( "a)\"x%2By%5E2=4\"
\n" ); document.write( " \"x%5E2%2By%5E2=16\"\r
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\n" ); document.write( "\n" ); document.write( "b) (x+1)Square + (y+1)Square=5
\n" ); document.write( " 2x-y=3
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Algebra.Com's Answer #457724 by tommyt3rd(5050)\"\" \"About 
You can put this solution on YOUR website!
I will do a)\r
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\n" ); document.write( "\n" ); document.write( "\"x%2By%5E2=4\"
\n" ); document.write( " \"x%5E2%2By%5E2=16\"\r
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\n" ); document.write( "\n" ); document.write( "\"y%5E2=4-x\"\r
\n" ); document.write( "\n" ); document.write( "therefore\r
\n" ); document.write( "\n" ); document.write( " \"x%5E2%2B4-x=16\"\r
\n" ); document.write( "\n" ); document.write( "so that\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2-x-12=0\"\r
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\n" ); document.write( "\n" ); document.write( "x=4 or x=-3\r
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\n" ); document.write( "\n" ); document.write( "x=-3 leads to \"y=++sqrt%287%29\" or \"y=+-+sqrt%287%29\"\r
\n" ); document.write( "\n" ); document.write( "x=4 leads to \"y=0\"\r
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