document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=752229>Question 752229</A>: <I><SPAN STYLE=\"word-break: break-all;\"> if A lies in the second quadrant and 3tan A +4=0 then the value of 2 cot A-5 cos A+sin A is equal to? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #457723 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=457723\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> if A lies in the second quadrant and 3tan A +4=0 then the value of 2 cot A-5 cos A+sin A is equal to?<BR>\n" );
document.write( "***<BR>\n" );
document.write( "3tanA+4=0<BR>\n" );
document.write( "tanA=-4/3<BR>\n" );
document.write( "Working with a 3-4-5 reference right triangle in Q2<BR>\n" );
document.write( "cotA=-3/4<BR>\n" );
document.write( "cosA=-3/5<BR>\n" );
document.write( "sinA=4/5<BR>\n" );
document.write( "..<BR>\n" );
document.write( "2 cot A-5 cos A+sin A<BR>\n" );
document.write( "=2(-3/4)-5(-3/5)+4/5<BR>\n" );
document.write( "=-6/4+3+4/5<BR>\n" );
document.write( "=-3/2+3+4/5<BR>\n" );
document.write( "=-15/10+30/10+8/10<BR>\n" );
document.write( "=23/10 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );